(9/x^2+1)=(x+3)/4

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Solution for (9/x^2+1)=(x+3)/4 equation: 



(9/x^2+1)=(x+3)/4

We move all terms to the left:

(9/x^2+1)-((x+3)/4)=0



Domain of the equation: x^2+1)!=0

x∈R



We get rid of parentheses

9/x^2-((x+3)/4)+1=0

We calculate fractions

We do not support expression: x^3

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